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Let's review and memorize the formula for calculating area, perimeter of a rhombus and diagonal of a rhombus in the article below.
Table of Contents
The area of a rhombus is measured by the size of the surface area, which is the visible flat part of the rhombus.

The area of a rhombus is equal to half the product of the lengths of the two diagonals , the formula is as follows:
In there:
Sis the area of the rhombus.d1and d2are the two diagonals of a rhombus.Example of calculating the area of a rhombus.
Lesson 1: There is a rhombus-shaped piece of cardboard with two intersecting diagonals of lengths 6 cm and 8 cm respectively. What is the area of the rhombus-shaped piece of cardboard?
Applying the method of calculating the area of a rhombus, we have d1 = 6 cm and d2 = 8 cm. We put it into the formula and get the following result:
S = 1/2 x (d1 x d2) = 1/2 (6 x 8) = 1/2 x 48 = 24 cm2

In which: a: side of rhombus
Example 1 : Given rhombus ABCD, with rhombus edge = 4cm, angle A = 35 degrees. Calculate the area of rhombus ABCD.
Solution: Applying the formula, we have a = 4, angle = 35 degrees. We substitute into the formula as follows:
S = a2 x sinA = 42 x sin(35) = 9.176 (cm2)
The perimeter of a rhombus is calculated by adding the lengths of the lines surrounding the shape, which is also the line surrounding the entire area.

To calculate the perimeter of a rhombus, we calculate the sum of the lengths of the four sides. The specific formula is as follows:
In there:
Pis the perimeter of a rhombus.ais the length of the side of the rhombus.For example: Given a rhombus ABCD with equal side lengths and 7 cm. What is the perimeter of this rhombus?
According to the formula for calculating the perimeter of a rhombus introduced above, we have a = 7 cm. Thus, the perimeter of rhombus ABCD will be calculated as follows:
P (ABCD) = ax 4 = 7 x 4 = 28 cm
A rhombus is a quadrilateral with four equal sides. It is a parallelogram with two adjacent sides equal or a parallelogram with two diagonals perpendicular to each other.

In this article, Quantrimang.com will reintroduce effective formulas for calculating the area and perimeter of a rhombus for your study and work.
Example 1:
Given rhombus ABCD with side AD = 4m, angle DAB = 30 degrees. Calculate the area of rhombus ABCD.
Prize:
Because ABCD is a rhombus, the triangles formed are isosceles triangles. Let I be the midpoint of the two diagonals, so AI is perpendicular to BD, angle IAB = 15 degrees.
Therefore, AI = AB. cos IAB = 4. Cos 15 = 3.84m.
Consider the right triangle ABI, according to the Pythagorean theorem, we have:
BI2= AB2- AI2= 1.25m
So BI = 1.1m
AC = 2. AI = 7.68m
BD = 2. BI = 2.2m
Based on the formula for calculating the area of a rhombus, we have the area of a rhombus ABCD = ½ . AC . BD = 8.45(m2)
Example 2: Given a rhombus with a side length of 6cm and one of its angles has a measure of 60°, calculate the area of the rhombus.
With these facts, you will not have any basis to calculate the area of a rhombus. You will have to rely on the properties of rhombuses, properties of equilateral triangles , and how to calculate the sides in a right triangle to calculate the diagonal of the rhombus. The steps are as follows:
Step 1: Draw a picture and note the known facts.

Step 2: Applying the properties of a rhombus we have:
, diagonal AC is the bisector of angle A, so the angle will be equal to 1/2 angle and equal to 60°. (The sum of the interior angles of a quadrilateral is 360°, the sum of the interior angles of a triangle is 180°). Thus, triangle ADC will be an equilateral triangle => side AC is 6cm. I is the midpoint of AC => AI=3cm.
Step 3: Calculate the length of DI
Triangle DIA is right-angled at I, side DI will be calculated as follows:
=> cm
Step 4: Calculate the area of rhombus ABCD:
Example 3: Given rhombus ABCD with side length 13cm, two diagonals intersect at H.
Calculate the area of rhombus ABCD knowing that BH is one and a half times AH.
Solution:
ABCD is a rhombus, so AH is perpendicular to BH at H, then triangle ABH is right-angled at H.
Let BH= 2a, then AH =3a.
According to the Pythagorean theorem we have: AH²+ BH²= AB² ⇒9a²+4a²=13 ⇒13a²=13 ⇒a=1
Therefore AH= 3cm, BH= 2cm or AC= 6 cm, BD= 4cm
The area of the rhombus is: S = 6.4/2= 12cm².
Example 4 :
Given rhombus MNPQ, angle A = 30o, perimeter = 20m, midpoint of diagonal is I. What is the area of rhombus MNPQ?
Solution
The length of the side of the rhombus is a = P : 4 = 20 : 4 = 5m
Because the triangles created by rhombuses are all isosceles triangles, the triangle created from the midpoint of diagonal I, points M, N will be created by angle IMN = 15o
Length of half diagonal MI = MN x cos IMN = 5 x cos150 = 4.8m
Applying the Pythagorean theorem in right triangle MNI we have: NI = 1.4m
Diagonal length NQ = 2 x NI = 2 x 1.4 = 2.8m
The area of rhombus MNPQ is S = 2 x ½ x NQ x MI = 1 x ½ x 2.8 x 4.8 = 13.44m2
Answer: 13.44m2
If you have any questions related to the formula for calculating the area and perimeter of a rhombus, please leave a comment below to discuss and answer together. Thank you for following the article.
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