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Let's review and memorize the formula for calculating area, perimeter of a rhombus and diagonal of a rhombus in the article below.
Table of Contents
The area of a rhombus is measured by the size of the surface area, which is the visible flat part of the rhombus.

The area of a rhombus is equal to half the product of the lengths of the two diagonals , the formula is as follows:
In there:
Sis the area of the rhombus.d1and d2are the two diagonals of a rhombus.Example of calculating the area of a rhombus.
Lesson 1: There is a rhombus-shaped piece of cardboard with two intersecting diagonals of lengths 6 cm and 8 cm respectively. What is the area of the rhombus-shaped piece of cardboard?
Applying the method of calculating the area of a rhombus, we have d1 = 6 cm and d2 = 8 cm. We put it into the formula and get the following result:
S = 1/2 x (d1 x d2) = 1/2 (6 x 8) = 1/2 x 48 = 24 cm2

In which: a: side of rhombus
Example 1 : Given rhombus ABCD, with rhombus edge = 4cm, angle A = 35 degrees. Calculate the area of rhombus ABCD.
Solution: Applying the formula, we have a = 4, angle = 35 degrees. We substitute into the formula as follows:
S = a2 x sinA = 42 x sin(35) = 9.176 (cm2)
The perimeter of a rhombus is calculated by adding the lengths of the lines surrounding the shape, which is also the line surrounding the entire area.

To calculate the perimeter of a rhombus, we calculate the sum of the lengths of the four sides. The specific formula is as follows:
In there:
Pis the perimeter of a rhombus.ais the length of the side of the rhombus.For example: Given a rhombus ABCD with equal side lengths and 7 cm. What is the perimeter of this rhombus?
According to the formula for calculating the perimeter of a rhombus introduced above, we have a = 7 cm. Thus, the perimeter of rhombus ABCD will be calculated as follows:
P (ABCD) = ax 4 = 7 x 4 = 28 cm
A rhombus is a quadrilateral with four equal sides. It is a parallelogram with two adjacent sides equal or a parallelogram with two diagonals perpendicular to each other.

In this article, Quantrimang.com will reintroduce effective formulas for calculating the area and perimeter of a rhombus for your study and work.
Example 1:
Given rhombus ABCD with side AD = 4m, angle DAB = 30 degrees. Calculate the area of rhombus ABCD.
Prize:
Because ABCD is a rhombus, the triangles formed are isosceles triangles. Let I be the midpoint of the two diagonals, so AI is perpendicular to BD, angle IAB = 15 degrees.
Therefore, AI = AB. cos IAB = 4. Cos 15 = 3.84m.
Consider the right triangle ABI, according to the Pythagorean theorem, we have:
BI2= AB2- AI2= 1.25m
So BI = 1.1m
AC = 2. AI = 7.68m
BD = 2. BI = 2.2m
Based on the formula for calculating the area of a rhombus, we have the area of a rhombus ABCD = ½ . AC . BD = 8.45(m2)
Example 2: Given a rhombus with a side length of 6cm and one of its angles has a measure of 60°, calculate the area of the rhombus.
With these facts, you will not have any basis to calculate the area of a rhombus. You will have to rely on the properties of rhombuses, properties of equilateral triangles , and how to calculate the sides in a right triangle to calculate the diagonal of the rhombus. The steps are as follows:
Step 1: Draw a picture and note the known facts.

Step 2: Applying the properties of a rhombus we have:
, diagonal AC is the bisector of angle A, so the angle will be equal to 1/2 angle and equal to 60°. (The sum of the interior angles of a quadrilateral is 360°, the sum of the interior angles of a triangle is 180°). Thus, triangle ADC will be an equilateral triangle => side AC is 6cm. I is the midpoint of AC => AI=3cm.
Step 3: Calculate the length of DI
Triangle DIA is right-angled at I, side DI will be calculated as follows:
=> cm
Step 4: Calculate the area of rhombus ABCD:
Example 3: Given rhombus ABCD with side length 13cm, two diagonals intersect at H.
Calculate the area of rhombus ABCD knowing that BH is one and a half times AH.
Solution:
ABCD is a rhombus, so AH is perpendicular to BH at H, then triangle ABH is right-angled at H.
Let BH= 2a, then AH =3a.
According to the Pythagorean theorem we have: AH²+ BH²= AB² ⇒9a²+4a²=13 ⇒13a²=13 ⇒a=1
Therefore AH= 3cm, BH= 2cm or AC= 6 cm, BD= 4cm
The area of the rhombus is: S = 6.4/2= 12cm².
Example 4 :
Given rhombus MNPQ, angle A = 30o, perimeter = 20m, midpoint of diagonal is I. What is the area of rhombus MNPQ?
Solution
The length of the side of the rhombus is a = P : 4 = 20 : 4 = 5m
Because the triangles created by rhombuses are all isosceles triangles, the triangle created from the midpoint of diagonal I, points M, N will be created by angle IMN = 15o
Length of half diagonal MI = MN x cos IMN = 5 x cos150 = 4.8m
Applying the Pythagorean theorem in right triangle MNI we have: NI = 1.4m
Diagonal length NQ = 2 x NI = 2 x 1.4 = 2.8m
The area of rhombus MNPQ is S = 2 x ½ x NQ x MI = 1 x ½ x 2.8 x 4.8 = 13.44m2
Answer: 13.44m2
If you have any questions related to the formula for calculating the area and perimeter of a rhombus, please leave a comment below to discuss and answer together. Thank you for following the article.
In this article, we will guide you how to regain access to your hard drive when it fails. Let's follow along!
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